Optimal. Leaf size=409 \[ \frac {(5 b c-17 a d) (b c-a d)^2 \sqrt {x}}{2 b^5}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^{5/2}}{10 b^4}+\frac {d^2 (39 b c-17 a d) x^{9/2}}{18 b^3}+\frac {17 d^3 x^{13/2}}{26 b^2}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}+\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{4 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{4 \sqrt {2} b^{21/4}}+\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}} \]
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Rubi [A]
time = 0.31, antiderivative size = 409, normalized size of antiderivative = 1.00, number of steps
used = 13, number of rules used = 9, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {477, 478, 584,
217, 1179, 642, 1176, 631, 210} \begin {gather*} \frac {d x^{5/2} \left (17 a^2 d^2-39 a b c d+27 b^2 c^2\right )}{10 b^4}+\frac {\sqrt [4]{a} \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right ) (5 b c-17 a d) (b c-a d)^2}{4 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right ) (5 b c-17 a d) (b c-a d)^2}{4 \sqrt {2} b^{21/4}}+\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}+\frac {\sqrt {x} (5 b c-17 a d) (b c-a d)^2}{2 b^5}+\frac {d^2 x^{9/2} (39 b c-17 a d)}{18 b^3}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}+\frac {17 d^3 x^{13/2}}{26 b^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 217
Rule 477
Rule 478
Rule 584
Rule 631
Rule 642
Rule 1176
Rule 1179
Rubi steps
\begin {align*} \int \frac {x^{7/2} \left (c+d x^2\right )^3}{\left (a+b x^2\right )^2} \, dx &=2 \text {Subst}\left (\int \frac {x^8 \left (c+d x^4\right )^3}{\left (a+b x^4\right )^2} \, dx,x,\sqrt {x}\right )\\ &=-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}+\frac {\text {Subst}\left (\int \frac {x^4 \left (c+d x^4\right )^2 \left (5 c+17 d x^4\right )}{a+b x^4} \, dx,x,\sqrt {x}\right )}{2 b}\\ &=-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}+\frac {\text {Subst}\left (\int \left (\frac {(5 b c-17 a d) (b c-a d)^2}{b^4}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^4}{b^3}+\frac {d^2 (39 b c-17 a d) x^8}{b^2}+\frac {17 d^3 x^{12}}{b}+\frac {-5 a b^3 c^3+27 a^2 b^2 c^2 d-39 a^3 b c d^2+17 a^4 d^3}{b^4 \left (a+b x^4\right )}\right ) \, dx,x,\sqrt {x}\right )}{2 b}\\ &=\frac {(5 b c-17 a d) (b c-a d)^2 \sqrt {x}}{2 b^5}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^{5/2}}{10 b^4}+\frac {d^2 (39 b c-17 a d) x^{9/2}}{18 b^3}+\frac {17 d^3 x^{13/2}}{26 b^2}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}-\frac {\left (a (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{a+b x^4} \, dx,x,\sqrt {x}\right )}{2 b^5}\\ &=\frac {(5 b c-17 a d) (b c-a d)^2 \sqrt {x}}{2 b^5}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^{5/2}}{10 b^4}+\frac {d^2 (39 b c-17 a d) x^{9/2}}{18 b^3}+\frac {17 d^3 x^{13/2}}{26 b^2}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}-\frac {\left (\sqrt {a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {\sqrt {a}-\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{4 b^5}-\frac {\left (\sqrt {a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {\sqrt {a}+\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{4 b^5}\\ &=\frac {(5 b c-17 a d) (b c-a d)^2 \sqrt {x}}{2 b^5}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^{5/2}}{10 b^4}+\frac {d^2 (39 b c-17 a d) x^{9/2}}{18 b^3}+\frac {17 d^3 x^{13/2}}{26 b^2}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}-\frac {\left (\sqrt {a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{8 b^{11/2}}-\frac {\left (\sqrt {a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{8 b^{11/2}}+\frac {\left (\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{8 \sqrt {2} b^{21/4}}+\frac {\left (\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{8 \sqrt {2} b^{21/4}}\\ &=\frac {(5 b c-17 a d) (b c-a d)^2 \sqrt {x}}{2 b^5}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^{5/2}}{10 b^4}+\frac {d^2 (39 b c-17 a d) x^{9/2}}{18 b^3}+\frac {17 d^3 x^{13/2}}{26 b^2}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}+\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}-\frac {\left (\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{4 \sqrt {2} b^{21/4}}+\frac {\left (\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{4 \sqrt {2} b^{21/4}}\\ &=\frac {(5 b c-17 a d) (b c-a d)^2 \sqrt {x}}{2 b^5}+\frac {d \left (27 b^2 c^2-39 a b c d+17 a^2 d^2\right ) x^{5/2}}{10 b^4}+\frac {d^2 (39 b c-17 a d) x^{9/2}}{18 b^3}+\frac {17 d^3 x^{13/2}}{26 b^2}-\frac {x^{5/2} \left (c+d x^2\right )^3}{2 b \left (a+b x^2\right )}+\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{4 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{4 \sqrt {2} b^{21/4}}+\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}-\frac {\sqrt [4]{a} (5 b c-17 a d) (b c-a d)^2 \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{8 \sqrt {2} b^{21/4}}\\ \end {align*}
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Mathematica [A]
time = 0.57, size = 301, normalized size = 0.74 \begin {gather*} \frac {\frac {4 \sqrt [4]{b} \sqrt {x} \left (-9945 a^4 d^3+117 a^3 b d^2 \left (195 c-68 d x^2\right )+13 a^2 b^2 d \left (-1215 c^2+1404 c d x^2+68 d^2 x^4\right )+a b^3 \left (2925 c^3-12636 c^2 d x^2-2028 c d^2 x^4-340 d^3 x^6\right )+12 b^4 x^2 \left (195 c^3+117 c^2 d x^2+65 c d^2 x^4+15 d^3 x^6\right )\right )}{a+b x^2}-585 \sqrt {2} \sqrt [4]{a} (b c-a d)^2 (-5 b c+17 a d) \tan ^{-1}\left (\frac {\sqrt {a}-\sqrt {b} x}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}\right )+585 \sqrt {2} \sqrt [4]{a} (b c-a d)^2 (-5 b c+17 a d) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}{\sqrt {a}+\sqrt {b} x}\right )}{4680 b^{21/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.15, size = 327, normalized size = 0.80 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 499, normalized size = 1.22 \begin {gather*} \frac {{\left (a b^{3} c^{3} - 3 \, a^{2} b^{2} c^{2} d + 3 \, a^{3} b c d^{2} - a^{4} d^{3}\right )} \sqrt {x}}{2 \, {\left (b^{6} x^{2} + a b^{5}\right )}} - \frac {{\left (\frac {2 \, \sqrt {2} {\left (5 \, b^{3} c^{3} - 27 \, a b^{2} c^{2} d + 39 \, a^{2} b c d^{2} - 17 \, a^{3} d^{3}\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}}} + \frac {2 \, \sqrt {2} {\left (5 \, b^{3} c^{3} - 27 \, a b^{2} c^{2} d + 39 \, a^{2} b c d^{2} - 17 \, a^{3} d^{3}\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}}} + \frac {\sqrt {2} {\left (5 \, b^{3} c^{3} - 27 \, a b^{2} c^{2} d + 39 \, a^{2} b c d^{2} - 17 \, a^{3} d^{3}\right )} \log \left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} {\left (5 \, b^{3} c^{3} - 27 \, a b^{2} c^{2} d + 39 \, a^{2} b c d^{2} - 17 \, a^{3} d^{3}\right )} \log \left (-\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}}\right )} a}{16 \, b^{5}} + \frac {2 \, {\left (45 \, b^{3} d^{3} x^{\frac {13}{2}} + 65 \, {\left (3 \, b^{3} c d^{2} - 2 \, a b^{2} d^{3}\right )} x^{\frac {9}{2}} + 351 \, {\left (b^{3} c^{2} d - 2 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} x^{\frac {5}{2}} + 585 \, {\left (b^{3} c^{3} - 6 \, a b^{2} c^{2} d + 9 \, a^{2} b c d^{2} - 4 \, a^{3} d^{3}\right )} \sqrt {x}\right )}}{585 \, b^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 2014 vs.
\(2 (317) = 634\).
time = 0.79, size = 2014, normalized size = 4.92 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.95, size = 600, normalized size = 1.47 \begin {gather*} -\frac {\sqrt {2} {\left (5 \, \left (a b^{3}\right )^{\frac {1}{4}} b^{3} c^{3} - 27 \, \left (a b^{3}\right )^{\frac {1}{4}} a b^{2} c^{2} d + 39 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{2} b c d^{2} - 17 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{3} d^{3}\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{8 \, b^{6}} - \frac {\sqrt {2} {\left (5 \, \left (a b^{3}\right )^{\frac {1}{4}} b^{3} c^{3} - 27 \, \left (a b^{3}\right )^{\frac {1}{4}} a b^{2} c^{2} d + 39 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{2} b c d^{2} - 17 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{3} d^{3}\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{8 \, b^{6}} - \frac {\sqrt {2} {\left (5 \, \left (a b^{3}\right )^{\frac {1}{4}} b^{3} c^{3} - 27 \, \left (a b^{3}\right )^{\frac {1}{4}} a b^{2} c^{2} d + 39 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{2} b c d^{2} - 17 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{3} d^{3}\right )} \log \left (\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{16 \, b^{6}} + \frac {\sqrt {2} {\left (5 \, \left (a b^{3}\right )^{\frac {1}{4}} b^{3} c^{3} - 27 \, \left (a b^{3}\right )^{\frac {1}{4}} a b^{2} c^{2} d + 39 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{2} b c d^{2} - 17 \, \left (a b^{3}\right )^{\frac {1}{4}} a^{3} d^{3}\right )} \log \left (-\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{16 \, b^{6}} + \frac {a b^{3} c^{3} \sqrt {x} - 3 \, a^{2} b^{2} c^{2} d \sqrt {x} + 3 \, a^{3} b c d^{2} \sqrt {x} - a^{4} d^{3} \sqrt {x}}{2 \, {\left (b x^{2} + a\right )} b^{5}} + \frac {2 \, {\left (45 \, b^{24} d^{3} x^{\frac {13}{2}} + 195 \, b^{24} c d^{2} x^{\frac {9}{2}} - 130 \, a b^{23} d^{3} x^{\frac {9}{2}} + 351 \, b^{24} c^{2} d x^{\frac {5}{2}} - 702 \, a b^{23} c d^{2} x^{\frac {5}{2}} + 351 \, a^{2} b^{22} d^{3} x^{\frac {5}{2}} + 585 \, b^{24} c^{3} \sqrt {x} - 3510 \, a b^{23} c^{2} d \sqrt {x} + 5265 \, a^{2} b^{22} c d^{2} \sqrt {x} - 2340 \, a^{3} b^{21} d^{3} \sqrt {x}\right )}}{585 \, b^{26}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.16, size = 1850, normalized size = 4.52 \begin {gather*} \sqrt {x}\,\left (\frac {2\,c^3}{b^2}-\frac {2\,a\,\left (\frac {6\,c^2\,d}{b^2}+\frac {2\,a\,\left (\frac {4\,a\,d^3}{b^3}-\frac {6\,c\,d^2}{b^2}\right )}{b}-\frac {2\,a^2\,d^3}{b^4}\right )}{b}+\frac {a^2\,\left (\frac {4\,a\,d^3}{b^3}-\frac {6\,c\,d^2}{b^2}\right )}{b^2}\right )-x^{9/2}\,\left (\frac {4\,a\,d^3}{9\,b^3}-\frac {2\,c\,d^2}{3\,b^2}\right )+x^{5/2}\,\left (\frac {6\,c^2\,d}{5\,b^2}+\frac {2\,a\,\left (\frac {4\,a\,d^3}{b^3}-\frac {6\,c\,d^2}{b^2}\right )}{5\,b}-\frac {2\,a^2\,d^3}{5\,b^4}\right )-\frac {\sqrt {x}\,\left (\frac {a^4\,d^3}{2}-\frac {3\,a^3\,b\,c\,d^2}{2}+\frac {3\,a^2\,b^2\,c^2\,d}{2}-\frac {a\,b^3\,c^3}{2}\right )}{b^6\,x^2+a\,b^5}+\frac {2\,d^3\,x^{13/2}}{13\,b^2}-\frac {{\left (-a\right )}^{1/4}\,\mathrm {atan}\left (\frac {\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}+\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )}{b^{29/4}}\right )\,1{}\mathrm {i}}{8\,b^{21/4}}+\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}-\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )}{b^{29/4}}\right )\,1{}\mathrm {i}}{8\,b^{21/4}}}{\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}+\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )}{b^{29/4}}\right )}{8\,b^{21/4}}-\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}-\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )}{b^{29/4}}\right )}{8\,b^{21/4}}}\right )\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,1{}\mathrm {i}}{4\,b^{21/4}}+\frac {{\left (-a\right )}^{1/4}\,\mathrm {atan}\left (\frac {\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}-\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )\,1{}\mathrm {i}}{b^{29/4}}\right )}{8\,b^{21/4}}+\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}+\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )\,1{}\mathrm {i}}{b^{29/4}}\right )}{8\,b^{21/4}}}{\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}-\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )\,1{}\mathrm {i}}{b^{29/4}}\right )\,1{}\mathrm {i}}{8\,b^{21/4}}-\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (\frac {\sqrt {x}\,\left (289\,a^8\,d^6-1326\,a^7\,b\,c\,d^5+2439\,a^6\,b^2\,c^2\,d^4-2276\,a^5\,b^3\,c^3\,d^3+1119\,a^4\,b^4\,c^4\,d^2-270\,a^3\,b^5\,c^5\,d+25\,a^2\,b^6\,c^6\right )}{b^7}+\frac {{\left (-a\right )}^{1/4}\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )\,\left (17\,a^5\,d^3-39\,a^4\,b\,c\,d^2+27\,a^3\,b^2\,c^2\,d-5\,a^2\,b^3\,c^3\right )\,1{}\mathrm {i}}{b^{29/4}}\right )\,1{}\mathrm {i}}{8\,b^{21/4}}}\right )\,{\left (a\,d-b\,c\right )}^2\,\left (17\,a\,d-5\,b\,c\right )}{4\,b^{21/4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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